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Sagot :
9514 1404 393
Answer:
- about 2.6 half-lives
- 16% remains
Step-by-step explanation:
The number of half-lives is ...
(15000 yr)/(5770 yr/half-life) = 2.6 half-lives
__
Then the amount of C14 remaining after 15000 years is ...
0.5^2.6 ≈ 0.1649 ≈ 16%
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