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beginning at sea level a scuba diver dove 1 2/3 feet into the water , and then dove an additional 3 2/5 feet at what elevation is the scuba diver

Sagot :

MrRoyal

The given details are illustrations of addition and subtractions of fractions.  The scuba driver is at an elevation of [tex]-5\frac{1}{15}[/tex] ft below the sea  level.

Given that:

[tex]n_1 = 1\frac 23[/tex] --- the first dive

[tex]n_2 = 3\frac 25[/tex] ---- the additional dive

From the question, we understand that the diver starts at the sea level.

This is represented with 0ft.

So, the diver's elevation (d) is calculated as follows:

[tex]d = 0 - n_1 - n_2[/tex] --- we use subtraction because the diver is below the sea level

So, we have:

[tex]d = 0 - 1\frac 23 - 3\frac 25[/tex]

[tex]d = - 1\frac 23 - 3\frac 25[/tex]

Convert fractions

[tex]d = - \frac 53 - \frac{17}5[/tex]

Take LCM

[tex]d = \frac{-5 \times 5 - 17 \times 3}{15}[/tex]

[tex]d = \frac{-76}{15}[/tex]

Reduce fraction

[tex]d = -5\frac{1}{15}[/tex]

The above value means that the diver's elevation is at [tex]-5\frac{1}{15}[/tex] ft below the sea  level.

Read more about fractions at:

https://brainly.com/question/18134643

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