Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A ball is thrown upwards with initial velocity 20 m/s. After reaching maximum height, on the way down it strikes a bird which is 10 m above the ground. What is the velocity of the ball when it hits the bird?

Sagot :

qpwoeimxbflqhdurytnx
"a ball is thrown upwards with initial velocity 20 m/s. After reaching maximum height, on the way down it strikes a bird which is 10 m above the ground. What is the velocity of the ball when it hits the bird?"

I know acceleration would be -9.8 m/s^2 (to assume free fall), the initial velocity would be 20, and that the final position would be 10, but I don't know how to find the max height to then use to find the final velocity.

Just set this up as a quadratic function. I assume that we start from a height of zero, since you don't say.
h(t) = 20t - 4.9t^2
Now, you want to solve
20t - 4.9t^2 = 10
t = 0.583, 3.498
Since v=20-9.8t, that would make
v(3.498) = 20-9.8*3.498 = -14.28

You don't need to find the max height for this problem, but that occurs when v=0. So, h(2) = 20.4

Anyways goodluck!
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.