Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A ball is thrown upwards with initial velocity 20 m/s. After reaching maximum height, on the way down it strikes a bird which is 10 m above the ground. What is the velocity of the ball when it hits the bird?

Sagot :

qpwoeimxbflqhdurytnx
"a ball is thrown upwards with initial velocity 20 m/s. After reaching maximum height, on the way down it strikes a bird which is 10 m above the ground. What is the velocity of the ball when it hits the bird?"

I know acceleration would be -9.8 m/s^2 (to assume free fall), the initial velocity would be 20, and that the final position would be 10, but I don't know how to find the max height to then use to find the final velocity.

Just set this up as a quadratic function. I assume that we start from a height of zero, since you don't say.
h(t) = 20t - 4.9t^2
Now, you want to solve
20t - 4.9t^2 = 10
t = 0.583, 3.498
Since v=20-9.8t, that would make
v(3.498) = 20-9.8*3.498 = -14.28

You don't need to find the max height for this problem, but that occurs when v=0. So, h(2) = 20.4

Anyways goodluck!
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.