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Sagot :
Answer: 1.22x10^78 H atoms per Universe
Explanation: Lots of conversions, so watch for errors.
Mass of Sun:
V=(4/3)πr²
V = (4/3)(π)(7x10⁸m)² = 1.44x10²⁷ m³ or 1.44x10³³ cm³
Mass of Sun: (1.44x10³³ cm³)*(1.4g/cm³) = 2.02x10³³ g/sun
Suns/Milky Way = 1x10¹¹ suns/galaxy
Suns/Universe = (1x10¹¹ suns/galaxy)*(1x10¹⁰galaxies/universe) = 1x10²¹ suns/universe
Assunming all mass ins in the suns, mass of the universe is:
(1x10²¹ suns/universe)*(2.02x10³³ g/sun) = 2.02x10⁵⁴g/universe
Molar mass of H is 1 g/mole
1 mole = 6.02x10²³H atoms
H atoms/universe = (2.02x10⁵⁴g/universe)*(1 g H atoms/mole)*(6.02x10²³H atoms/mole) = 1.22x10⁷⁸ H atoms per universe.
Answer:
Number of atoms in the universe is [tex]\[1.201\times {{10}^{79}}\][/tex]
Explanation:
Calculate number of atoms in universe using CGS unit.
Step 1
Calculate mass of sun
[tex]\[\text{Mass of sun = Density }\times \text{ Volume}\][/tex]
Step 2
Insert the value of density and radius to calculate mass of sun
[tex]& \text{Mass of sun = 1}\text{.4}\times \frac{4}{3}\pi {{\left( 7\times {{10}^{10}} \right)}^{3}} \\ & \text{Mass of sun}=2.011\times {{10}^{33}}g \\ \end{align}[/tex]
Average atomic mass of hydrogen atom is [tex]\[1.008amu\][/tex]
Avogadro’s number is number of atoms in 1 mole of hydrogen.
Step 3
Calculate number of Hydrogen [tex]\[\left( {{N}_{H}} \right)\][/tex]atoms in sun
[tex]& {{N}_{H}}=\frac{\text{Mass of sun}}{\text{Molar mass of Hydrogen atom}}\times \text{Avogadro }\!\!'\!\!\text{ s }\text{Number} \\ & {{N}_{H}}=\frac{2.011\times {{10}^{33}}}{1.008}\times 6.02\times {{10}^{23}} \\ & {{N}_{H}}=1.201\times {{10}^{57}} \\[/tex]
Step 4
Calculate number of atoms[tex]\[\left( {{N}_{A}} \right)\][/tex] in our Milky Way galaxy
[tex]& {{N}_{A}}=\text{Number of stars}\times \text{Number of atoms in sun} \\ & {{N}_{A}}=1.00\times {{10}^{11}}\times 1.202\times {{10}^{57}} \\ & {{N}_{A}}=1.201\times {{10}^{68}} \\[/tex]
Step 5
Calculate number of atom in observable universe [tex]\[\left( {{N}_{Ao}} \right)\][/tex]
[tex]& {{N}_{Ao}}=\text{Number of galaxies }\times \text{ Number of atoms in our galaxy} \\ & {{N}_{Ao}}=1.00\times {{10}^{11}}\times 1.201\times {{10}^{68}} \\ & {{N}_{Ao}}=1.201\times {{10}^{79}} \\[/tex]
Learn more about universe here:
https://brainly.com/question/17525451
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