Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

write as a single logarithm 3-1/2(log6+log3-3log2)

Sagot :

konrad509
[tex]3-\dfrac{1}{2}\left(\log6+\log3-3\log2\right)=\\ \log10^3-\dfrac{1}{2}\left(\log\left(6\cdot3\right)-\log2^3\right)=\\ \log1000-\dfrac{1}{2}\left(\log18-\log8\right)=\\ \log1000-\dfrac{1}{2}\left(\log\dfrac{18}{8}\right)=\\ \log1000-\dfrac{1}{2}\left(\log\dfrac{9}{4}\right)=\\ \log1000-\log\left(\dfrac{9}{4}\right)^{\dfrac{1}{2}}=\\ \log1000-\log\sqrt{\dfrac{9}{4}}=\\ \log1000-\log\dfrac{3}{2}=\\ \log\dfrac{1000}{\frac{3}{2}}=\\ \log\left(1000\cdot\dfrac{2}{3}\right)=\\ \log\dfrac{2000}{3}[/tex]
Answer in document below.
View image Аноним
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.