Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
So here you're solving a system of equations. If A=the number of strokes Abby has, B=the number of strokes Brenda has, and C=the number of strokes Charda has, then your equations would be:
A-4=(A+B+C)/3
(A+B)+8=3C
A+B+C=192
If we look carefully, you can see that (A+B+C) can be seen in two equations (the first and third). So you could use substitution with that.
A-4=(192/3)
A-4=64
A=68
So now you know that Abby has 60 strokes, you can substitute that into any of the other equations. I chose the second and got:
68+B+8=3C
B+76=3C
B=3C-76
If you substitute this and Abby's score into the third equation, you get:
68+(3C-76)+C=192
4C-8=192
4C=200
C=50 strokes
A-4=(A+B+C)/3
(A+B)+8=3C
A+B+C=192
If we look carefully, you can see that (A+B+C) can be seen in two equations (the first and third). So you could use substitution with that.
A-4=(192/3)
A-4=64
A=68
So now you know that Abby has 60 strokes, you can substitute that into any of the other equations. I chose the second and got:
68+B+8=3C
B+76=3C
B=3C-76
If you substitute this and Abby's score into the third equation, you get:
68+(3C-76)+C=192
4C-8=192
4C=200
C=50 strokes
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.