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Sagot :
Answer:
8907.66 Joules
Explanation:
q=mCpΔT
where q is heat (Joules) m: mass (grams) Cp: Specific heat ΔT=change in temp (final - initial)
Specific heat of water is 4.182
q=30(4.182)(25-96)
q=-8907.66
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