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What is the landing velocity of an object that is dropped from a height of 49 m?

Sagot :

onyebuchinnaji

The landing velocity of the object is 31 m/s.

The given parameters;

height from which the object is released, h = 49 m

The landing velocity of the object is calculated by applying third equation of motion as shown below;

v² = u² + 2gh

where;

  • v is the landing velocity of the object
  • u is the initial velocity of the object
  • g is acceleration due to gravity = 9.8 m/s²
  • h is the height of fall given

The landing velocity of the object is calculated as;

v² = 0 + 2(9.8)(49)

v² = 960.4

v = √960.4

v = 30.99 m/s

v ≈ 31 m/s

Thus, the landing velocity of the object is 31 m/s.

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