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Find the probability that a random selected occupation has an Emotional Health Index Score between 80.5 and 82. (Round to three decimal places)

Sagot :

Supposing the distribution is uniform, we find that there is a 0.15 = 15% probability that a random selected occupation has an Emotional Health Index Score between 80.5 and 82.

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Uniform probability distribution:

  • Has two bounds, a and b.
  • The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

In this problem:

  • We suppose that scores are uniformly distributed between 75 and 85, thus [tex]a = 75, b = 85[/tex].

The probability between 80.5 and 82 is:

[tex]P(80.5 \leq X \leq 82) = \frac{82 - 80.5}{85 - 75} = 0.15[/tex]

0.15 = 15% probability that a random selected occupation has an Emotional Health Index Score between 80.5 and 82.

A similar problem is given at https://brainly.com/question/15855314