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A block of mass, m=4.80 kg is placed on the edge of a rough surface of height h = 0.5 2m as shown above. The block is released and moves until it stops momentarily after compressing a horizontal spring (with a spring constant k = 2,000 N/m) by a compression distance x = 12.1 cm. Find the work done by friction.

Sagot :

hamzaahmeds

This question can be easily solved by using the law of conservation of energy.

The work done by the friction is "9.9 J".

The law of conservation of energy applied to this condition gives the following equation:

[tex]Potential\ Energy\ Lost\ by\ Block = Energy\ Stored\ by\ Spring\ +\ Work\ done\ by\ friction\\\\mgh = \frac{1}{2}kx^2\ +\ W[/tex]where,

W = Work done by friction = ?

m = mass of the block = 4.8 kg

g = acceleration due to gravity = 9.81 m/s²

h = height = 0.52 m

k = spring constant = 2000 N/m

x = compression distance = 12.1 cm = 0.121 m

Therefore,

[tex](4.8\ kg)(9.81\ m/s^2)(0.52\ m)=\frac{1}{2}(2000\ N/m)(0.121\ m)^2+W\\W = 24.5\ J - 14.6\ J[/tex]

W = 9.9 J

Learn more about the law of conservation of energy here:

brainly.com/question/20971995?referrer=searchResults

The attached picture explains the law of conservation of energy.

View image hamzaahmeds
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