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If point (x,y) lies on the graph of y = f(c), then the graph f-1 (x) must contain the point
O (-X, -Y)
O (-7, -x)
Oly, x)
OC)


If Point Xy Lies On The Graph Of Y Fc Then The Graph F1 X Must Contain The Point O X Y O 7 X Oly X OC class=

Sagot :

If (a, b) lies on the graph of y = f(x), then f(a) = b.  

 

By definition the inverse of the function, f-1(x), is such that f-1(b) = a.

 

Therefore the point (b, a) must be on the graph of f-1(x).

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