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Graph AJKL and its image after a reflection in the line y = -3.
J(3,-5), K(4, -1), L(0, -3).


Sagot :

When a shape is reflected, it must be reflected across a line

See attachment for the graphs of JKL and its image

The given parameters are:

[tex]\mathbf{J = (3,-5)}[/tex]

[tex]\mathbf{K = (4,-1)}[/tex]

[tex]\mathbf{L = (0,-3)}[/tex]

The rule of reflection across line [tex]\mathbf{y = -3}[/tex] is:

[tex]\mathbf{(x,y) \to (x,-y - 6)}[/tex]

So, we have:

[tex]\mathbf{J' = (3,5 - 6) = (3,-1)}[/tex]

[tex]\mathbf{K' = (4,1 - 6) = (4,-5)}[/tex]

[tex]\mathbf{L' = (0,3 - 6) = (0,-3)}[/tex]

This means that, the coordinates of the image of JKL are:

[tex]\mathbf{J' = (3,-1)}[/tex]

[tex]\mathbf{K' = (4,-5)}[/tex]

[tex]\mathbf{L' = (0,-3)}[/tex]

See attachment for the graphs of JKL and its image

Read more about reflections at:

https://brainly.com/question/938117

View image MrRoyal