Answered

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Write the equation of a line that is
parallel to 3x + Oy = -9 through the
point (3, 3).

Sagot :

VirαtKσhli

Answer:

[tex]3x-y-6=0[/tex]

Step-by-step explanation:

Given equation of the line ,

[tex]\implies 3x + 0y = -9 [/tex]

Convert it into[tex] y = mx + c[/tex] form ,

[tex]\implies 0 = 3x + 9 [/tex]

Hence , the

  • [tex] m = 3 [/tex]

As we know that the slope of parallel lines is same . Hence on using slope point form ,

[tex]\implies y - y_1 = m(x - x_1) \\\\\implies y - 3 = 3 (x - 3) \\\\\implies y - 3 = 3x - 9 \\\\\implies 3x -9+3-y = 0 \\\\\implies 3x -y-6=0[/tex]

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