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3.3 points
Exactly 392 J will raise the temperature of 10.0 g of a metal from 25.0°C to 60.0°C. What is the specific heat capacity of the metal?
a. 1.12 J/g°C


Ob.0.893 J/g°Cc. 9.9 J/gºC
Od. 74.7 J/g°C
e. none of these

Sagot :

Eduard22sly

The specific heat capacity of the metal is 1.12 J/gºC

The correct answer to the question is Option A. 1.12 J/gºC

We'll begin by calculating the change in the temperature of the metal. This can be obtained as follow:

Initial temperature (T₁) = 25 °C

Final temperature (T₂) = 60 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 60 – 25

Change in temperature of metal (ΔT) = 35 °C

Finally, we shall determine the specific heat capacity of the metal. This can be obtained as follow:

Heat (Q) = 392 J

Mass of metal (M) = 10 g

Change in temperature of metal (ΔT) = 35 °C

Specific heat capacity of metal (C) =?

Q = MCΔT

392 = 10 × C × 35

392 = 350 × C

Divide both side by 350

C = 392 / 350

Specific heat capacity of metal = 1.12 J/gºC

Therefore, the specific heat capacity of the metal is 1.12 J/gºC.

Option A. 1.12 J/gºC gives the correct answer to the question.

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