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Sagot :
f(3) = 5 [5-3=2 diff]
f(4) = 8 [8-4=4 diff] (or 2 times larger than f(3)’s diff)
If that holds true, then continue the pattern:
f(5) = 13 [2 times f(4) diff = 8 so 5 + 8 = 13]
f(6) = 22
f(7) = 39
f(8) = 72
The only problem with my answer is that it could be times 2 or ^2. My answer above assumes times 2.
f(4) = 8 [8-4=4 diff] (or 2 times larger than f(3)’s diff)
If that holds true, then continue the pattern:
f(5) = 13 [2 times f(4) diff = 8 so 5 + 8 = 13]
f(6) = 22
f(7) = 39
f(8) = 72
The only problem with my answer is that it could be times 2 or ^2. My answer above assumes times 2.
Answer: f(7) = 17 & f(8) = 20
Step-by-step explanation:
We can use f(3) = 5 and f(4) = 8 to write points that we can turn into an equation, and then solve for f(7) and f(8).
f(3) = 5 can be written as (3 , 5)
f(4) = 8 can be written as (4 , 8)
The slope of this line using the slope (y₂ - y₁) ÷ (x₂ - x₁) = (8 - 5) ÷ (4 - 3)
= 3
The equation of the line can be written in the point-slope form (y - y₁) = m(x - x₁)); where (x₁ , y₁) = (3 , 5):
y - 5 = 3 (x - 3)
Now, f(7) occurs when x = 7
y - 5 = 3 (7 - 3)
y - 5 = 12
y = 17
∴ f(7) = 17
Now, f(8) occurs when x = 8
y - 5 = 3 (8 -3)
y - 5 = 15
y = 20
∴ f(8) = 20
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