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9(p+2)<=3(3p-5) solve the inequality

Sagot :

9(p+2)<=3(3p-5)

remove the brackets by multiplying the number outside the bracket by each term in the bracket

=9×p+9×2<=(3×3p)+3×-5

=9p+18<=9p-15

Group like terms

=9p-9p<=-15-18. NB: the positive 18 became negative 18 since it moved from one side of the equation to the other

=9p-9p<=-15-18

0<=33