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Sagot :
Dilation involves changing the size of a shape.
- See attachment for the graphs of ABC, A'B'C and A"B"C"
- A"B"C" is a dilation of A'B'C', with a scale factor of 1/4
From the given diagram, we have:
[tex]\mathbf{A = (4,-2)}[/tex]
[tex]\mathbf{B = (-2,-2)}[/tex]
[tex]\mathbf{C = (-2,2)}[/tex]
(a) Dilate by scale factor 2 with center (0,0)
We simply multiply the coordinates of ABC by 2
So, we have:
[tex]\mathbf{A' = 2 \times (4,-2) = (8,-4)}[/tex]
[tex]\mathbf{B' = 2 \times (-2,-2) = (-4,-4)}[/tex]
[tex]\mathbf{C' = 2 \times (-2,2) = (-4,4)}[/tex]
See attachment for the graph of A'B'C'
(b) Dilate by scale factor 2 with center (0,0)
We simply multiply the coordinates of ABC by 1/2
So, we have:
[tex]\mathbf{A" = \frac 12 \times (4,-2) = (2,-1)}[/tex]
[tex]\mathbf{B" = \frac 12 \times (-2,-2) = (-1,-1)}[/tex]
[tex]\mathbf{C' = \frac 12 \times (-2,2) = (-1,1)}[/tex]
See attachment for the graph of A"B"C'
(c) Is A"B"C" a dilation of A'B'C
Yes, A"B"C" is a dilation of A'B'C
- ABC is dilated by 2 to get A'B'C
- ABC is dilated by 1/2 to get A"B"C
So, the scale factor (k) from A'B'C' to A"B"C" is:
[tex]\mathbf{k = \frac{1/2}{2}}[/tex]
[tex]\mathbf{k = \frac 14}[/tex]
The scale factor (k) from A'B'C' to A"B"C" is 1/4
And the center is (0,0)
Read more about dilations at:
https://brainly.com/question/13176891
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