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Sagot :
The magnitude of the friction force is 600 Newton.
Given the following data:
- Mass of sprinter = 60 kg
- Initial velocity, U = 0 m/s (since the sprinter is starting from rest).
- Final velocity, V = 0 m/s
- Time, t = 0.20 seconds.
To find the magnitude of the friction force:
First of all, we would determine the acceleration of the sprinter by using the following formula;
[tex]a = \frac{V \; - \;U}{t}[/tex]
Where:
- a is the acceleration.
- V is the final velocity.
- U is the initial velocity.
- t is the time measured in seconds.
Substituting the given parameters into the formula, we have;
[tex]a = \frac{2 \;- \;0}{0.20} \\\\a = \frac{2}{0.20}[/tex]
Acceleration, a = 10 [tex]m/s^2[/tex]
Now, we would determine the magnitude of the friction force by using Newton's Second Law of Motion:
Mathematically, Newton's Second Law of Motion is given by this formula;
[tex]Force = mass[/tex] × [tex]acceleration[/tex]
[tex]Force = 60[/tex] × [tex]10[/tex]
Force = 600 Newton
Therefore, the magnitude of the friction force is 600 Newton.
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