At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
When copper-67 undergoes beta decay, the isotope that is produced is D. zinc-67.
Beta decay refers to a type of radioactive decay where a beta particle is emitted from an atomic nucleus, such that the original nuclide is transformed to an isobar of that nuclide.
It should be noted that in the case of Copper-67, it undergoes beta decay with a half-life of 59 hours and then becomes stable Zinc-67.
Read related link on:
https://brainly.com/question/24106092
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.