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Determine maximum and minimum value of the function y=4x-x^2 +3

Sagot :

discipulus

Answer:

[tex]y = - {x}^{2} + 4x + 3 \\ x = - \frac{b}{2a} \\ x = - \frac{4}{2( - 1)} \\ x = 2 \\ y = f(2) = 4(2) - {(2)}^{2} + 3 \\ y = 7 \\ \therefore \: maximum \: at \binom{2}{7} [/tex]

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