Answered

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A stadium has 80,000 seats. Seats sell for $40 in Section A, $20 in Section B, and $10 in Section C. The number of
seats in section Cequals the total number of seats in sections A and B. Suppose the stadium takes $1,500,000 from each
sold-out event. How many seats does each section hold?

Sagot :

hellow4327

Answer:

There are 26,000 seats in Section A, 14,100 in section B & 11,900 in section C

Step-by-step explanation:

Section B = x

Section C = y

Section A = x + y

Step 1-

Total number of seats = 52000

x + y + (x + y) = 52000

x + y + x + y = 52000

2x + 2y = 52000

x + y = 26000

x = 26000 - y

Step 2-

Total amount collected = $1,370,500

20x + 15y + 35(x + y) = 1,370,500

20x + 15y + 35x + 35y = 1,370,500

55x + 50y = 1,370,500

11x + 10y = 274,100

Step 3-

x = 26000 - y  

11x + 10y = 274,100

Finding y

11 (26000 - y) + 10y = 274,100

286000 - 11y + 10y = 274,100

y = 11,900    

Finding x

x = 26000 - y

x = 26000 - 11900

x = 14,100

Section B = 14,100

Section C = 11,900

Section  A = 14,100 + 11,900 = 26,000

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