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Balancing Equations.

Balancing Equations class=

Sagot :

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Answer:

(1)N2+3F2 -> 2NF3

Explanation:

This problem can be done a few ways.


This reaction is a redox reaction, so it will be treated as such:

First, we count the number of N atoms there are on both sides
the left has 2 and the right has 1. The LCM of 2 and 1 is 2, so the lcm of nitrogen is 2.
Similarly, the lcm of fluorine is 6, since the lcm of 2 and 3 is 6.

The LCM is also the number of atoms that there are on both sides, so there are 2 nitrogens and 6 fluorines on both sides, which isn't hard to distribute.

Here's another example:
P4 + O2 -> P2O5
lcm of 4 and 2 is 4, so there are 4 Phosphoruses on both side
Lcm of 2 and 5 is 10, so there are 10 oxygen atoms on both side


Once we know the total amount of atoms on both side, distributing them isn't very hard

(P4+5O2-> 2P2O5)

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