Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

use the discriminant to find the number and type of solution for x^2+6x=-9​

Sagot :

VectorFundament120

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

[tex] \displaystyle \large{D = {b}^{2} - 4ac}[/tex]

First, arrange the expression or equation in ax^2+bx+c = 0.

[tex] \displaystyle \large{ {x}^{2} + 6x = - 9}[/tex]

Add both sides by 9.

[tex] \displaystyle \large{ {x}^{2} + 6x + 9 = - 9 + 9} \\ \displaystyle \large{ {x}^{2} + 6x + 9 = 0}[/tex]

Compare the coefficients so we can substitute in the formula.

[tex] \displaystyle \large{a {x}^{2} + bx + c = {x}^{2} + 6x + 9 }[/tex]

  • a = 1
  • b = 6
  • c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

[tex] \displaystyle \large{D = {6}^{2} - 4(1)(9)} \\ \displaystyle \large{D = 36 - 36} \\ \displaystyle \large{D = 0}[/tex]

Since D = 0, the type of solution is one real root.

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.