Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A stone is dropped into a well and is heard to hit the water 2.27 s after being dropped. Determine the depth of the well.​

Sagot :

Answer:

25.25m

Explanation:

The Depth or distance would be:

d = acceleration x time² / 2

If the stone was held at a dead stop until dropped, acceleration is equal to gravity which is 9.8 m/s²

So then you have:

d = (9.8m/s²)(2.27s)² / 2  or (9.8m/s²)(2.27s)(2.27s) / 2

the seconds cancel each other out and you're left with meters.

d = 25.25 m

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.