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Three consecutive integers such the three times the smallest is 12 more then the largest.
Find the integers.


Sagot :

x - 1st integer
x+1 - 2nd integer
x+2 - 3rd integer

[tex]3x=x+2+12\\ 2x=14\\ x=7\\ x+1=8\\ x+2=9[/tex]

Those integers are 7,8,9.

The three consecutive integers are 7, 8 and 9.

Given that, three consecutive integers such the three times the smallest is 12 more than the largest.

We need to find the three consecutive integers.

What are consecutive integers?

Consecutive integers are those numbers that follow each other. They follow in a sequence or in order. For example, a set of natural numbers are consecutive integers.

Let the three consecutive integers be x, (x + 1) and (x + 2).

According to the given question, 3 times the smallest integer is 12 more than the largest integer.

So, 3x=(x+2)+12

⇒3x=x+14

⇒2x=14

⇒x=7

Thus, x=7, x+1=8 and x+2=9

Therefore, the three consecutive integers are 7, 8 and 9.

To learn more about the consecutive integers visit:

https://brainly.com/question/1767889.

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