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Sagot :
The acceleration of the object after 3 seconds of fall is -9.8 m/s².
The given parameters;
- Initial velocity of the object, u = 0
- Time of motion of the object, t = 3 seconds
Acceleration is the change in velocity per change in time of motion.
The acceleration of the object after 3 seconds of fall is calculated as follows;
- Since the object is in free fall, the object experiences only acceleration due to gravity.
- The magnitude of this acceleration due to gravity is 9.8 m/s²
- The direction of this acceleration is downwards
Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².
Learn more here: https://brainly.com/question/13197713
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