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Sagot :
The dimensions of a playing field that has a perimeter of 528 yards are:
- Length = 213 yards
- Width = 51 yards
Recall:
Perimeter of a rectangle = 2(L + W)
We can represent the length and width using variables to form algebraic expressions as follows:
- Let W represent the width
- Width = W
- Length = (4W + 9) yards
- Perimeter = 528 yards
The following equation would be created to find the value of W:
2(L + W) = Perimeter
- Substitute
2[(4W + 9) + W} = 528
- Solve for W
[tex]2(4W + 9 + W) = 528\\\\[/tex]
- Add like terms
[tex]2(5W + 9) = 528\\\\10W + 18 = 528\\[/tex]
- Subtract 18 from each side
[tex]10W = 528 - 18\\\\10W = 510[/tex]
- Divide both sides by 10
W = 51
Width is the rectangular playing field is 51 yards
Find the Length:
Length = (4W + 9) yards
- Plug in the value of W
Length = 4(51) + 9 = 213 yards
Therefore, the dimensions of a playing field that has a perimeter of 528 yards are:
- Length = 213 yards
- Width = 51 yards
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https://brainly.com/question/18869010
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