twash1871
Answered

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A function includes ordered pairs (−2, 3), (0, −1), (1, 0), (3, 8), and (5, 24). Which point could not be the part of this function?

Sagot :

MrRoyal

A relation or an ordered pair may or may not be a function.

An ordered pair will only be a function when the x and y values are unique

The options are not given, so I will provide a general explanation

For an ordered pair to be a function, all the y values must point to different x values.

Take for instance, the given ordered pair

[tex]\mathbf{(-2, 3), (0, -1), (1, 0), (3, 8), (5, 24)}[/tex]

The above represents a function, because the y-values have different x-values

However, the following ordered pair is not a function

[tex]\mathbf{(-2, 3), (0, -1), (1, 0), (3, 8), (3, 9), (5, 24)}[/tex]

The reason is that:

y-values 9 and 8 have the same x-value (3)

Read more about ordered pairs and functions at:

https://brainly.com/question/11482687

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