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a golfer hits a golf ball giving it an initial velocity 30m/s at an angle 45° from the horizontal. ignoring air resistance on a flat golf course, how far does the ball travel before first contacting the ground?

Sagot :

Answer:

90 meters.

Explanation:

The correct answer is: B.) 90 m

The distance travelled by the ball before hitting the ground first is 90 m

Data obtained from the question

  • Initial velocity (u) = 30 m/s
  • Angle of projection (θ) = 45°
  • Acceleration due to gravity (g) = 10 m/s²
  • Range (R) =?

How to determine the range

The distance travelled (i.e range) of the ball can be obtained as follow:

R = u²Sine(2θ) / g

R = 30² × Sine (2×45) / 10

R = 900 / 10

R = 90 m

Thus, the range of the ball is 90 m

Learn more about projectile motion:

https://brainly.com/question/20326485

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