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Sagot :
Answer:
• Considering the (x - 6):
[tex]{ \tt{(x - 6) = 0}} \\ \\ { \boxed{ \tt{ \: \: x _{1} = 6 \: \: }}}[/tex]
• considering the (7x - 3):
[tex]{ \tt{7x - 3 = 0}} \\ { \tt{7x = 3}} \\ \\ { \boxed{ \tt{ \: \: x _{2} = \frac{3}{7} \: \: }}}[/tex]
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