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Sagot :
The final specific volume in m³/kg is 0.0313 m³/kg.
Since [tex]Pv^{0.5} = constant[/tex] where P = pressure and v = specific volume, we have
Since [tex]P_{1} v_{1}^{0.5} = P_{2} v_{2}^{0.5}[/tex] where
- P₁ = initial pressure = 250 kPa,
- v₁ = initial specific volume = V₁/m where
- V₁ = initial volume of gas = 1.5 m³ and
- m = mass of gas = 3 kg. so, v₁ = V₁/m = 1.5 m³/3 kg = 0.5 m³/kg,
- P₂ = final pressure = 100 kPa,
- v₂ = final specific volume of gas
Final Specific volume
Making v₂ subject of the formula, we have
[tex]v_{2} = v_{1} ( \frac{P_{1} }{P_{2} }) ^{2}[/tex]
Substituting the values of the variables into the equation, we have
[tex]v_{2} = v_{1} ( \frac{P_{1} }{P_{2} }) ^{2}[/tex]
[tex]v_{2} = 0.5 \frac{m^{3} }{kg} ( \frac{250 kPa }{100 kPa }) ^{2}\\v_{2} = 0.5 \frac{m^{3} }{kg} ( \frac{25}{10}) ^{2}\\v_{2} = 0.5 \frac{m^{3} }{kg} ( 0.25) ^{2}\\v_{2} = 0.5 \frac{m^{3} }{kg} (0.0625)\\v_{2} = 0.0313 \frac{m^{3} }{kg}[/tex]
The final specific volume in m³/kg is 0.0313 m³/kg.
Learn more about specific volume of gas here:
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