goatloverhawaiibm
Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting


Options in picture below!

Pleaseeee Hurry!!!!!!!

Let G Be The Universal Gravitational Constant And Mp Be The Mass Of The Planet A Satellite Is OrbitingOptions In Picture BelowPleaseeee Hurry class=

Sagot :

oladayoademosu

The speed of the satellite is v = √(Gmp/r)

At the geostationary orbit, the gravitational force of attraction of the planet on the satellite equals the centripetal force on the satellite.

Let F = gravitational force  

[tex]F = \frac{Gm_{p}m }{r^{2} }[/tex] where G = universal gravitational constant, mp = mass of the planet, m = mass of satellite and r = radius of geostationary orbit.

Also, the centripetal force F'

[tex]F^{'} = \frac{mv^{2}}{r}[/tex] where m = mass of satellite, v = speed of satellite and r = radius of geostationary orbit.

Since both forces are equal,

F = F'

[tex]\frac{Gm_{p}m }{r^{2} } = \frac{mv^{2} }{r}[/tex]

[tex]v^{2} = \frac{Gm_{p} }{r} \\v = \sqrt{\frac{Gm_{p} }{r} }[/tex]

So, the speed of the satellite is v = √(Gmp/r)

Learn  more about speed of a satellite here:

https://brainly.com/question/20162935

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.