Step-by-step explanation:
3)
Given expression is x(6x-8y)-x²(6x-5y)
=>6x²-8xy-6x³+5x²y
=> x(6x-8y-6x²+5xy)
x(6x-8y)-x²(6x-5y) = x(6x-8y-6x²+5xy)
If the given problem like this
x(6x-5y)-x²(6x-5y)
=> (6x-5y)(x-x²)
=> (6x-5y)(x)(1-x²)
=> (6x-5y)(x)(1+x)(1-x)
4)
Given expression is 9m(p-3q)-3n(p-3q)
=> (p-3q)(9m-3m)
=> (p-3q)3(3m-n)
=> 3(p-3q)(3m-n)
9m(p-3q)-3n(p-3q) = 3(p-3q)(3m-n)
5)
Given that ax+ay-bx-by
=> a(x+y)-b(x+y)
=> (x+y)(a-b)
ax+ay-bx-by = (x+y)(a-b)
6)
Given that
a²+2a+ab+2b
=> (a²+ab)+(2a+2b)
=> a(a+b)+2(a+b)
=> (a+b)(a+2)
a²+2a+ab+2b = (a+b)(a+2)
7)
Given that
2ax+bx+2ay+by
=> (2ax+2ay)+(bx+by)
=> 2a(x+y)+b(x+y)
=> (x+y)(2a+b)
2ax+bx+2ay+by = (x+y)(2a+b)
8)
Given that
xy-pq+qy-px
=> (xy+qy)-(pq+px)
=> y(x+q)-p(q+x)
=> y(x+q)-p(x+q)
=> (x+q)(y-p)
xy-pq+qy-px = (x+q)(y-p)
9)
Given that
1+p+pq+p²q
=> (1+p)+(pq+p²q)
=> 1(1+p)+pq (1+p)
=> (1+p)(1+pq)
1+p+pq+p²q = (1+p)(1+pq)
10)
Given that
2a-4b-xa+2bx
=> (2a-4b)-(xa-2bx)
=> 2(a-2b)-x(a-2b)
=> (a-2b)(2-x)
2a-4b-xa+2bx = (a-2b)(2-x)
Hope this helps!!
