Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Would anyone care to explain how to get through this problem in the photo? I'm at a complete dead end! Any help would be appreciated!

Would Anyone Care To Explain How To Get Through This Problem In The Photo Im At A Complete Dead End Any Help Would Be Appreciated class=

Sagot :

Trancescient

Step-by-step explanation:

The slope of the equation tangent to y = f(x) at x = 4 is equal to f'(4). Therefore,

[tex]m = f'(4) = \dfrac{1}{(4)^2 - 9} = \dfrac{1}{7}[/tex]

We also know that the line passes through the tangent point at (4, -1) so we can write the slope-intercept form of the equation as

[tex]y = mx + b \Rightarrow -1 = \dfrac{1}{7}(4) + b[/tex] or

[tex]b = -\dfrac{11}{7}[/tex]

so our equation is

[tex]y = \dfrac{1}{7}x -\dfrac{11}{7}[/tex]

or in standard form,

[tex]x - 7y = 11[/tex]

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.