Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Would anyone care to explain how to get through this problem in the photo? I'm at a complete dead end! Any help would be appreciated!

Would Anyone Care To Explain How To Get Through This Problem In The Photo Im At A Complete Dead End Any Help Would Be Appreciated class=

Sagot :

Trancescient

Step-by-step explanation:

The slope of the equation tangent to y = f(x) at x = 4 is equal to f'(4). Therefore,

[tex]m = f'(4) = \dfrac{1}{(4)^2 - 9} = \dfrac{1}{7}[/tex]

We also know that the line passes through the tangent point at (4, -1) so we can write the slope-intercept form of the equation as

[tex]y = mx + b \Rightarrow -1 = \dfrac{1}{7}(4) + b[/tex] or

[tex]b = -\dfrac{11}{7}[/tex]

so our equation is

[tex]y = \dfrac{1}{7}x -\dfrac{11}{7}[/tex]

or in standard form,

[tex]x - 7y = 11[/tex]

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.