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Sagot :
• We’re trying to inscribe a square inside of a circle
• If we bisect the square, we get two triangles with right angles
• Circle diameter = 1.4m = hypothenuse of triangles = 2 * radius
• 2r = r * sqrt(2) + r * sqrt(2)
• We want to know the value of r * sqrt(2) is since that’s one of the sides of the inscribed square
• (0.7) * sqrt(2) = 0.99 m = side of inscribed square
• 0.99m < 1 m side
• So we are just barely not able to cut a 1m sided square in a circle piece of tin with 1.4m diameter
• If we bisect the square, we get two triangles with right angles
• Circle diameter = 1.4m = hypothenuse of triangles = 2 * radius
• 2r = r * sqrt(2) + r * sqrt(2)
• We want to know the value of r * sqrt(2) is since that’s one of the sides of the inscribed square
• (0.7) * sqrt(2) = 0.99 m = side of inscribed square
• 0.99m < 1 m side
• So we are just barely not able to cut a 1m sided square in a circle piece of tin with 1.4m diameter
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