Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
With the projectile launch we can find that the response for the initial velocity of the salmon is 3.68 m/s
Projectile launching is an application of kinematics for movement in two dimensions. In this case they indicate the jump distance x = 2.61 m and the jump height y = 0.277 m and the angle of 39.3º and ask the initial velocity.
Let's use trigonometry for the initial velocity.
cos 39.3 = [tex]\frac{v_x}{v}[/tex]
sin 39.3 = [tex]\frac{v_y}{v}[/tex]
vₓ = v cos 39.3
= v sin 39.3
Suppose that when you reach the height of the waterfall you are in the highest part of the jump, therefore the vertical velocity is zero.
[tex]v_y^2 = v_{oy}^2 -2 g y[/tex]
0 = - 2 g y
[tex]v_{oy}[/tex] = [tex]\sqrt{2gy}[/tex]
Let's calculate
[tex]v_{oy} = \sqrt{2 \ 9.8 \ 0.277}[/tex]
= 2.33 m / s
The relationship of the initial velocity and the angle.
= v sin 39.3
v = [tex]\frac{ v_{oy}}{son 39.3}[/tex]
v = 2.33 / sin 39.3
v = 3.68 m / s
In conclusion using projectile launch we can find the initial velocity of the salmon is 3.68 m / s.
Learn more here: brainly.com/question/15063198
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
