Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

In a running competition, a bronze, silver and gold medal must be given to the top
three girls and top three boys. If 11 boys and 11 girls are competing, how many
different ways could the six medals possibly be given out?

Sagot :

danielgeyfman

Assuming there are no ties

Answer:

980100

Step-by-step explanation:

Let's start with the boys(we could also start with girls, it doesn't matter).

We can "choose" one of 11 boys for the gold medal. That athlete can't win any more medals, so there are 10 boys left.

We can then "choose" one of the 10 boys remaining for the silver medal. That athlete can't win any more medals, so there are 9 boys left.

We can lastly "choose" one of the 9 boys remaining for the bronze medal.

That makes 11 possible choices for gold medal * 10 possible choices for silver medal * 9 possible choices for bronze medal = 990 possible choices(for boys).

We can do the exact same for the girls, leaving us with 990 possible choices for the girls.

We then multiply the possible choices together to get 990*990=980100 possible ways to hand out the six medals

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.