At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Please solve this for me using substitution

Please Solve This For Me Using Substitution class=

Sagot :

Answer:

1. 2x + y = 5

y = -2x - 5

2. x^2 + y^2 = 5

sub 1. into 2.

x^2 + (-2x - 5)^2 -5 = 0

x^2+ 4x^2 - 20x + 25 - 5 = 0

5x^2 - 20x + 20 = 0

5(x^2 - 4x + 5) = 0

5(x-2)^2 = 0

x = 2

sub x into 1.

2(2) + y = 5

y = 1

x = 2, y = 1

Step-by-step explanation:

See 2x + y = 5 as equation 1, and see x^2 + y^2 = 5 as equation 2.

Isolate equation 1's y, and sub the equation into equation 2.

The common factor of the new equation is 5, which divides the whole thing by 5, then find the answer, and further sub the answer into the equation 1 since it is easier to do so, therefore, the answer is x = 2, y = 1.