preethamprethu55
Answered

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bosm93

Answer:

Hello there are only 2 real solutions where x_1 = 11, x_2 = 7, x_3 = 3 and x_1 = 4, x_2 = 7, x_3 = 10

Step-by-step explanation:

Lets begin with arithmetic progression we know that we need some d which we will add to our x_1 to get x_2, so let's write it : x + (x+d) +(x+2d) = 21 and x*(x+d)*(x+2d) = 231 and that should be it.

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