Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Michelle has two fair 3-sided spinners. Michelle spins each spinner once. Each spinner lands on a number. Michelle multiplies these two numbers together to get her score. Work out the probability that Michelle’s score is at least 8

Sagot :

novastar9
What are the numbers on the 3 sides of the spinners?

Using probability of independent events, it is found that there is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

In this problem:

  • Two fair 3-sided spinners are span, and their values are multiplied.
  • The only way to get an score of at least 8 is spinning two threes.
  • For each spinner, there is a [tex]\frac{1}{3}[/tex] probability of spinning a 3, and the spinners are independent.

Hence:

[tex]P(A \cap B) = P(A)P(B) = \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}[/tex]

There is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

You can learn more about independent events at https://brainly.com/question/25715148

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.