Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Michelle has two fair 3-sided spinners. Michelle spins each spinner once. Each spinner lands on a number. Michelle multiplies these two numbers together to get her score. Work out the probability that Michelle’s score is at least 8

Sagot :

novastar9
What are the numbers on the 3 sides of the spinners?

Using probability of independent events, it is found that there is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

In this problem:

  • Two fair 3-sided spinners are span, and their values are multiplied.
  • The only way to get an score of at least 8 is spinning two threes.
  • For each spinner, there is a [tex]\frac{1}{3}[/tex] probability of spinning a 3, and the spinners are independent.

Hence:

[tex]P(A \cap B) = P(A)P(B) = \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}[/tex]

There is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

You can learn more about independent events at https://brainly.com/question/25715148

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.