ariamontogomery4
Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

5a). Sodium reacts with excess oxygen to form sodium peroxide, Na,0,. 2Na + 02 → Na,02 Calculate the maximum mass of sodium peroxide formed when 4.60 g of sodium is burnt in excess oxygen. (A, values: Na = 23.0, 0 = 16.0)

5b). Tin oxide (IV) is reduced to tin by carbon. Carbon monoxide is also formed. Sno2 + 20 > Sn + 2C0 Calculate the mass of carbon that exactly reacts with 14.0 g of tin(IV) oxide. Give your answer to 3 significant figures. (A, values: C = 12.0,0 = 16.0, Sn =118.7)​

Sagot :

adioabiola

5a) The maximum mass of sodium peroxide formed when 4.60 g of sodium is burnt in excess oxygen is; 7.8g of Sodium peroxide

5b) The mass of carbon that exactly reacts with 14.0g of tin(IV) oxide is; 2.23g of Carbon.

For questions (5a)

Sodium reacts with excess oxygen to form Sodium peroxide as follows;

  • 2Na + 02 → Na202.

Molar mass of sodium and sodium peroxide are 23 and 78 respectively.

Since 2 units of sodium produces one unit of sodium peroxide.

Therefore,

  • 46g of sodium = 78g of Na2O2.

  • 4.60g of sodium = xg of Na2O2.

  • x = (78 × 4.6)/46

x = 7.8g of Na2O2

For question (5b)

Tin oxide (IV) is reduced to tin by carbon. Carbon monoxide is also formed as follows;

  • Sno2 + 2C > Sn + 2C0

From stoichiometry,

  • 24g of Carbon = 150.7g of tin(IV) oxide.

  • xg of carbon = 14g of tin(IV) oxide

By Cross-product,

  • x = (14× 24)/150.7

x = 2.23g of carbon

Read more:

https://brainly.com/question/19290948

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.