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Sagot :
Answer:
Step-by-step explanation:
What you are looking for is the height of the water after the sphere enterred
first you find the volume of the water in the container
height of water in cylinder (h) =3/4 x 30cm =22.5 cm
diameter (d) = 12cm radius = d/2 =12cm /2 =6cm
Volume (V1)=[tex]\pi[/tex]r^2h= 22/7 x (6cm)^2 x 22.5cm =22/7 x 36cm^2 x 22.5cm
=2545 cm^3
Then you find the volume of the sphere
Diameter = d = 8cm radius = r = 8cm/2 =4cm
π =22/7
Volume (V2 )=(4/3) πr^3 = (4/3) π(4cm)^3 = (4/3) x 22/7 x64cm^3 =268cm^3
total volume after the sphere entered =V1 +V2 =(2545 +268)cm^3
=2813cm^3
now yoy use the volume formula but make height the subject
V=πr^2h h=V/πr^2h =2813cm^3 /(22/7) x (6cm)^2
=2813cm^3 x 7 /22 x36cm^2
=19691cm^3 / 792cm^2
=24.9 cm
therefore the height of the water in the container is 24.9 cm
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