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Steve is a nuclear physicist that is studying one radioactive element. Initially, he has 100 kg of that element, but he discovered that that
amount decreases following the equation N(t)= 100(2.72) raised to
-0.060
However, for his experiments it is better to express
this equation in the form N(t) = 100 * a' Help Steve to find the adequate value for a. Round your answer to the nearest
hundredth.

Steve Is A Nuclear Physicist That Is Studying One Radioactive Element Initially He Has 100 Kg Of That Element But He Discovered That That Amount Decreases Follo class=

Sagot :

The question is an illustration of equivalent equations

The approximated value of a is 0.94

The given parameters are:

[tex]\mathbf{N(t) = 100(2.72)^{-0.060t}}[/tex]

[tex]\mathbf{N(t) = 100a^t}[/tex]

Equate both expressions to solve for a

[tex]\mathbf{ 100a^t = 100(2.72)^{-0.060t}}[/tex]

Divide both sides by 100

[tex]\mathbf{a^t = (2.72)^{-0.060t}}[/tex]

By comparison

[tex]\mathbf{a = (2.72)^{-0.060}}[/tex]

Using a calculator, we have:

[tex]\mathbf{a = 0.94172882931}[/tex]

Approximate

[tex]\mathbf{a = 0.94}[/tex]

Hence, the approximated value of a is 0.94

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