kimninou123
Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A ski hill is angled 20° above the horizontal. If a skier starts from rest at the top of the hill, how fast will she be traveling after she has traveled 62 m 62 ⁢ m down the slope? Assume that friction is negligible.

Sagot :

Answer:

20 m/s

Explanation:

First, we calculate for the acceleration down the incline using [tex]a = gsin\theta[/tex].

a = (9.80)sin(20°)

a = 3.35

Then, we use one of the kinematics equations, [tex]{v_{f}}^{2} = {v_{i}}^{2} + 2 a\Delta s[/tex].

[tex]v_{i}[/tex] = 0 m/s

a = 3.35

[tex]\Delta s[/tex] = 62 m

[tex]v_{f} = \sqrt{2(3.35)(62)}[/tex]

[tex]v_{f} =20.381 = 20 m/s[/tex]

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.