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What is the equation of the line that passes through the point (5,-2) and has a
slope of 6/5?
Answer:
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Sagot :

Smillat

Answer:

y = 6/5x - 2

Step-by-step explanation:

use y = mx+ c

m = slope

c = y intercept

y = 6/5x - 2

djtwinx017
Given the point (5, -2), and slope = 6/5

Plug in the values into the slope-intercept formula:

y = mx + b
Where:
slope (m) = 6/5
b = y-intercept


We have to solve for the y-intercept. The y-intercept is the point on the graph where it crosses the y-axis. It is also the value of y when x = 0.

y = mx + b
-2 = 6/5(5) + b
-2 = 6 + b

Subtract 6 from both sides to solve for y-intercept, b:
-2 – 6 = b
-8 = b

Therefore, the equation of the line that passes through (5,-2) and has a slope of 6/5 is:
y = 6/5x - 8

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