The specific heat of the metal is 2.4733 J/g°C.
Given the following data:
- Initial temperature of water = 25.0°C
- Final temperature of water = 29.0°C
- Temperature of metal = 203.0°C
We know that the specific heat capacity of water is 4.184 J/g°C.
To find the specific heat of the metal (J/g°C):
Heat lost by metal = Heat gained by water.
[tex]Q_{metal} = Q_{water}[/tex]
Mathematically, heat capacity or quantity of heat is given by the formula;
[tex]Q = mc\theta[/tex]
Where:
- Q is the heat capacity or quantity of heat.
- m is the mass of an object.
- c represents the specific heat capacity.
- ∅ represents the change in temperature.
Substituting the values into the formula, we have:
[tex]30(203)c = 400(4.184)(29 \; -\; 20)\\\\6090c = 1673.6(9)\\\\6090c = 15062.4\\\\c = \frac{15062.4}{6090}[/tex]
Specific heat capacity of metal, c = 2.4733 J/g°C
Therefore, the specific heat of the metal is 2.4733 J/g°C.
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