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Sagot :
The endpoint of the line segments in each scenario are below;
- we have: (8,-3)
- we have: (-25,-6)
- we have: (-1,26)
- we have: (29,-13)
- we have: (14,12)
From straight line geometry, it is evident that the midpoint coordinates is given as follows;
x = (x2 + x1)/2
x = (x2 + x1)/2y = (y2 + y1)/2
Consequently, the other endpoint coordinates, x2 and y2 can be calculated as follows;
x2 = 2x - x1
x2 = 2x - x1y2 = 2y - y1
Therefore,
For Situation 1:
x2 = (2×5) - 2
x = 8
y2 = (2×1) - 5
y2 = -3.
Therefore, we have: (8,-3)
For Situation 2:
- x2 = (2×-10) - 5
x = -25
- y2 = (2×-2) - 2
y2 = -6.
Therefore, we have: (-25,-6)
For Situation 3:
- x2 = (2×4) - 9
x = -1
- y2 = (2×8) - (-10)
y2 = 26.
Therefore, we have: (-1,26)
For Situation 4:
- x2 = (2×10) - (-9)
x = 29
- y2 = (2×-3) - 7
y2 = -13.
Therefore, we have: (29,-13)
For Situation 5:
- x2 = (2×4) - (-6)
x = 14
- y2 = (2×8) - 4
y2 = 12.
Therefore, we have: (14,12)
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