Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Tomas and Tasha were hiking at a speed of 3.5 mph. On their way back, they were tired and their speed was 2 mph. How long was the route if the way back took them 1 hour and 30 minutes longer?

Sagot :

Answer: Time: Approximately 2 hours and 21 minutes

Length: 6 miles

If this doesn't answer your question please read the explanation.

Step-by-step explanation:

1 hour and 30 minutes is 3/2 of an hour.

Therefore, we have them traveling at 2 mph for 3/2 hours.

distance = rate x time

2 mph * 3/2 = 3 miles.

3 * 2 = 6 miles.

time = distance/rate

Then there is 3.5 mph

3 miles/3.5 mph = 6/7 of an hour.

Adding them: 33/14 is reached (hours)

Approximately 2 hours and 21 minutes.

 To get the length of the route use the expression for speed,

Distance = Speed × Time

Length of the route is 7 miles.

It's given in the question,

 Speed of Tomas and Tasha initially = 3.5 mph

Therefore, distance travelled by both with the speed of 2 mph one way will be,

 Distance = 3.5t [Here, t = time ]

Speed of both while coming back = 2 mph

And the time taken = t + (1 hour 30 minutes)

                                 = (t + 1.5) hours

Therefore, distance travelled while coming back = Speed × Time

                                                                                  = 2(t + 1.5)

Since, length of the route is same both ways,

3.5t = 2(t + 1.5)

3.5t = 2t + 3

3.5t - 2t = 3

1.5t = 3

t = 2 hours

Now substitute the value of t in the expression to get the distance of the route,

Distance = 3.5t

               = 3.5 × 2

               = 7 miles

 Therefore, route was 7 miles long.

Learn more,

https://brainly.com/question/1955818