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Sagot :
Usando un sistema de ecuaciones, se encuentra que la rapidez inicial del primer ninõ es 4.95 m/s.
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- Consideramos que la rapidez inicial de el primer ninõ es x, y de el segundo es y.
El primer niño rebota 1.5 veces más alto que el segundo.
O sea:
[tex]x = 1.5y[/tex]
La rapidez inicial del segundo niño es de 3.3 m/s.
Esto implica que [tex]y = 3.3[/tex]
¿Cuál es la rapidez (m/s) inicial del primer niño?
[tex]x = 1.5y = 1.5(3.3) = 4.95[/tex]
La rapidez inicial del primer ninõ es 4.95 m/s.
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