Answered

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The length of the base of a rectangular solid is 12 dm and the width is 5 dm. What should be the height of the rectangular solid so that its volume is smaller than the volume of a cube with a side of 9 dm?

Sagot :

The height of the rectangular solid must be less than 12.15 dm.

Length of the solid = 12 dm

Width of the solid = 5dm

Height of the solid = H

Volume of the cube will be:

= 9dm × 9dm × 9dm

= 729 dm³

Therefore, to calculate the height of the solid goes thus;

Height = 729 / (12 × 5)

Height = 729/60

Height = 12.15

Therefore, since the volume has to be smaller than the volume of a cube with a side of 9 dm, then the height will be less than 12.15 dm.

In conclusion, the height is less than 12.15 dm.

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