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Sagot :
The height of the rectangular solid must be less than 12.15 dm.
Length of the solid = 12 dm
Width of the solid = 5dm
Height of the solid = H
Volume of the cube will be:
= 9dm × 9dm × 9dm
= 729 dm³
Therefore, to calculate the height of the solid goes thus;
Height = 729 / (12 × 5)
Height = 729/60
Height = 12.15
Therefore, since the volume has to be smaller than the volume of a cube with a side of 9 dm, then the height will be less than 12.15 dm.
In conclusion, the height is less than 12.15 dm.
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